[quote][√R X (100-√M)
/quote]

so what does that equation give? u sure R should be sqrt

acewoonder wrote:√R X (100-√M

In words this is "The square root of deathstars times (100 minus the square root of the moon's diameter)"

bruteforce wrote:

[√R X (100-√M)
/quote]

so what does that equation give? u sure R should be sqrt

It's to test out the number of deathstars you send against a moon. Say you send 15 RIPs against a 8k moon. √8000 = 89.4427190999158. 100 - 89.4427190999158 = 10.5572809000842. The square root of 15 equals 3.87283346207416885. 3.87283346207416885 times 10.5572809000842 equals 40.888173107259. So you would have a 40.88% chance to destroy a moon by sending 15 RIPs.

For those of you adverse to doing math, it's the first link.

viewtopic.php?f=2&t=2977

I believe that this formula becomes inaccurate if the moon size is above 9k though, haven't ever popped a moon that big so I don't know for sure.

Is it still impossible to pop or even obtain a 10k moon?

It's impossible to pop, and nearly impossible to obtain.

So this is good to know. If the moon is 10k It can not be popped. But if it is under 10k even 9999. You can still pop it with this foumla?

yes because all of the numbers for potetial moon diameters will fit into this formula.unless it is under 100[there aren't any that small I've heard of] I think.and you can't have a zero diameter moon.so I am pretty sure everymoon under 9999 that you can get on zorg is calcuable.

Dr_triad3 wrote:everymoon under 9999 that you can get on zorg is calcuable.

And the only size over that is a size nobody has yet to be known to have. Unless Weresloth has found it yet. >.>

Oh, people were expecting me to do that?